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Re: Stealth and Scattering Armor bonus
SHIELD DEPLEATERS are smaller and more effective than normal weapons. They are the big equalizers for Shields vs Armor debate.
2 shots at 50% accuracy do not equal 1 shot at 100% accuracy. Two shots at 50% should break down to 75% for one hit, 25% for both hits, and 25% both miss. It should be the same as formula for repeated dice throws. That is why ECM and Combat Sensors are so important. Is anyone here a Mathamagician at probability and odds? I can't find the link I was looking for. |
Re: Stealth and Scattering Armor bonus
Wardad:
This is the math you look for. Yesterday I have spent two hours inventing this. Just check what all those abbreviations mean. ((TH sqared with AAW)!)/(100 sqared with AAW!))*AWW +CAM -CDM + E For your 50% chance: s=sqared 50%s(2weapons)! --------------- 100%s(2weapons)! 50s(2) 50s(1) ------ + --------- = 0.75 100s(2) 100(1) http://forum.shrapnelgames.com/images/icons/icon12.gif |
Re: Stealth and Scattering Armor bonus
Wardad:
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Re: Stealth and Scattering Armor bonus
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(25% x 2) + (50% x 1) + (25% x 0) = 100% So you can expect an average of one hit per volley of double-shots @ 50% If you fire N shot volleys, at 1/N accuracy, you'll get 1 hit per volley on average. |
Re: Stealth and Scattering Armor bonus
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No wonder I am having some difficulty understanding the underlying premises/conclusions of some of the Posts being made by the participants. http://forum.shrapnelgames.com/images/icons/icon7.gif Even with my having a good math background. http://forum.shrapnelgames.com/images/icons/shock.gif I read what you guys are posting with a great deal of interest. http://forum.shrapnelgames.com/images/icons/icon6.gif This is great stuff. [ March 21, 2003, 16:19: Message edited by: tbontob ] |
Re: Stealth and Scattering Armor bonus
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I didn't check your usage of it so if in fact you intended to add the numbers the answer might still might be right. There are math symbols for doing addition as you suggest, but they are different from the ! operation. Slick. |
Re: Stealth and Scattering Armor bonus
BTW, if you want a fast formula for calculating the sum of "n+(n-1)+(n-2)+...+2+1", it's n*(n+1)/2.
The idea is that you're finding the sum of "n" terms of an arithmetic progression; the generic formula is: Sum=(n/2)*(A+L) Where: A is the first term in the series L is the Last term in the series n is the number of terms http://forum.shrapnelgames.com/images/icons/icon10.gif http://forum.shrapnelgames.com/images/icons/shock.gif http://forum.shrapnelgames.com/image...s/rolleyes.gif [ March 21, 2003, 16:25: Message edited by: DirectorTsaarx ] |
Re: Stealth and Scattering Armor bonus
I admit I didnīt remember the symbol is multiplicative, not additive. What is important is the usage. I also didnīt know how to say the wole formula is to be repeated AAW times with % changing. But then - itīs about five years I did some math.
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