Re: Strategy guide?
 

Now, you realize that the squirrel isn't going to explode like that unless it tries to mate with an anti-squirrel.

Then you turn 2Kg of squirrel + almost 0 energy
into
0Kg of mass + 1.8 * 10^17 J of energy

Velocity has nothing to do with it. Nuclear reactions have nothing to do with it either.

The simple fact is that for every Joule of energy that is released, the mass of the system goes down by:
1/C^2

What the 50 megaton thing indicates, is that if you weighed your nuke, set it off, collected all of the remains, you would find that it weighs less than before, and that it weighs about one squirrel-mass less.

The sun loses a couple of kilograms each day, from all the energy it spews into space.

Re: Strategy guide?
 

Nuclear weapons (and all explosives) are rated in megatons by their explosive force. A 50 megaton bomb would explode with the same force and destructive power of 50 million tons of TNT. I doesn't have any thing to do with weighing the bomb.

Re: Strategy guide?
 

Yeah, but, that squirrel needs an ignition device and some sort of chain-reaction accelerator (usually provided by Tritium)....he then becomes a Voting member of the UN http://www.shrapnelgames.com/ubb/images/icons/icon7.gif

Spyder, Chairman of the Arachnid Consortium

[This message has been edited by Spyder (edited 26 February 2001).]

Re: Strategy guide?
 

Arggh! Don't you see?

The 50 Million Tons of TNT you pile up and explode turns into:

(50 Million Tons - 1 KG) of ash.

A 500KG Nuke rated at 50Megatons would turn into

(500KG - 1KG)= 499KG of ash.

The 1KG squirrel that releases a 50Megaton BLast turns into

(1KG - 1KG) = 0Kg of ash


A 50Megaton bLast is 9x10^16 J of energy
THEREFORE, a 50Megaton bLast is 1KG of Mass going byebye as energy.

This is not a nuclear squirrel, but an antimatter squirrel. That's the only way to get a 50Megatons bLast out of 1Kg of material.

E=MC^2 means that for your 50MT bLast, your mass goes down by 1KG. if you started with 1KG, you have ZERO mass left. The only way for that to happen is matter-antimatter annihilation.

Now, by measuring the energy released, you also happen to be measuring the mass lost by the device. (Since M=E/C^2)

Even for nukes, the mass lost is a tiny fraction of what you started with. All that means is that nukes are horribly inefficient at generating energy.

Re: Strategy guide?
 

Wow. http://www.shrapnelgames.com/ubb/images/icons/shock.gif

tic

Re: Strategy guide?
 

Well, I TRIED to lighten this, but.....<shakes his head>

Suicide Junkie....Unless I dramatically failed Physics and didn't know it...E=MC^2 is the formula with which you convert matter to energy. It has nothing to do with loss of mass during a nuclear reaction (there's a whole nother, page-long, equation for that http://www.shrapnelgames.com/ubb/images/icons/icon7.gif ).

Spyder, Chairman of the Arachnid Consortium (A Nuke-free Society)

Re: Strategy guide?
 

Please sir,... mercy mercy,... my he'd 'urts
no more science explanations pleazzzzzzzzz

(nice squirell by the way)

Re: Strategy guide?
 

From what I understand the loss of mass in a nuclear reaction is converted directly to energy at E=mc^2. That is party what makes a nuclear explosion so powerful. When the nucleous is split (where talking fission) here the resulting smaller nucleii don't add up to the same mass. The rest is pure energy. Of course this is usually a small fraction of the original critical mass. (btw this is usually on the order of fractions of grams if I remember correctly).

That is why anti-matter bombs are potentially so powerful (atleast 100's to 1000's times more powerful than nuclear fission devices). Because instead of losing a small amount of matter in the explosion you get 100% conVersion or the orignal mass (not less than 1%).

Re: Strategy guide?
 

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Lastseer:
From what I understand the loss of mass in a nuclear reaction is converted directly to energy at E=mc^2. That is party what makes a nuclear explosion so powerful. When the nucleous is split (where talking fission) here the resulting smaller nucleii don't add up to the same mass. The rest is pure energy. Of course this is usually a small fraction of the original critical mass. (btw this is usually on the order of fractions of grams if I remember correctly).

That is why anti-matter bombs are potentially so powerful (atleast 100's to 1000's times more powerful than nuclear fission devices). Because instead of losing a small amount of matter in the explosion you get 100% conVersion or the orignal mass (not less than 1%).<HR></BLOCKQUOTE>

Yep, I'll buy that...its figuring exactly how much mass is lost (as energy) that is the long formula of which I spoke. Of course, I'm old & gray and don't remember much....

Spyder, Chairman of the Arachnid Consortium

Re: Strategy guide?
 

So this squirrel has to hit something (to transfer the kinetic energy, which however would be inefficient) and be made of antimatter. Wow thats one rare squirrel. Plus the velocity you used would probably make the squirrel into mush as it is.