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Re: Chance of Arrival in Unit Reinforcement
I like simple math and was never called to be a mathematician, in ASL there are folks that can recite the probability of rolling 2d6 for various things, in those days (and even to this day) I just squeeze my dice a litter tighter and whisper a prayer and roll the bones. Probably why I am not a gambler or risk taker in real life...lol
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Re: Chance of Arrival in Unit Reinforcement
Han Solo (and probably zovs66) should look away now...
For those that want the maths: Use the “not” trick. If probability of a unit arriving is 20%, then the probability of not arriving is 80% (0.2 and 0.8 respectively). Not arriving(X) in a number of turns(N) is X ^ N. Therefore The chance they arrive by a certain turn is 1 - X ^ N. e.g.: The chance of appearance in 1 turn is 20%, in 2 turns is 1 - (0.8 ^ 2) = 36% , in 3 turns is 1 - (0.8 ^ 3) = 48.8%, in 4 turns is 1-(0.8 ^ 4) = 59%, in 5 turns is 1-(0.8 ^ 5) = 67%, etc. It never becomes a certainty, but there is a 99% chance that they will have arrived by turn 21! |
Re: Chance of Arrival in Unit Reinforcement
You lost me on
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Re: Chance of Arrival in Unit Reinforcement
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Thanks for all contributions. Informative. <br> |
Re: Chance of Arrival in Unit Reinforcement
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