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-   -   # of members ? (http://forum.shrapnelgames.com/showthread.php?t=9614)

Fyron June 8th, 2003 09:57 PM

Re: # of members ?
 
Gravity is constant in that the rate of change of the force due to gravity is constant. http://forum.shrapnelgames.com/images/icons/icon12.gif

PvK June 8th, 2003 09:59 PM

Re: # of members ?
 
I think you need to study anti-logic to quantify Fryon. http://forum.shrapnelgames.com/images/icons/icon12.gif

PvK

Jack Simth June 8th, 2003 10:28 PM

Re: # of members ?
 
Quote:

Originally posted by Imperator Fyron:
Gravity is constant in that the rate of change of the force due to gravity is constant. http://forum.shrapnelgames.com/images/icons/icon12.gif
<font size="2" face="Verdana, Helvetica, sans-serif">That only works in specialized circumstances; perhaps gravity is constant in that that G, the gravitational constant, is constant.

David E. Gervais June 8th, 2003 10:47 PM

Re: # of members ?
 
Well, I'm definately a 'Constant', and that's alot better than being a 'Variable' IHMO. http://forum.shrapnelgames.com/images/icons/icon12.gif

hmmm,.. but then again my post count is always changing, so I might be a 'variable' disguised as a 'constant'.

Come to think of it, many of the people here would best be described as 'Regulars',..

So I'm happy to announce I'm a regular guy. http://forum.shrapnelgames.com/images/icons/tongue.gif

Cheers! http://forum.shrapnelgames.com/images/icons/icon10.gif

P.S. I thought Gravity was 'relitive' not 'constant'. And if I'm not wrong it's relitive to mass, right?

[ June 08, 2003, 21:49: Message edited by: David E. Gervais ]

Jack Simth June 8th, 2003 11:07 PM

Re: # of members ?
 
Force from gravity is relative, sure:

F = G((M * m)/(d^2))

Where F is the magnitude of the force due to gravity, G is the gravitational constant (it is only sort of constant, as it depends on the units used), M and m are the two masses involved and d is the distance between the two masses. The direction is towards the other object.

Also, as Acceleration = Force/Mass, the acceleration is also relative.

Kamog June 9th, 2003 12:43 AM

Re: # of members ?
 
Quote:

Originally posted by David E. Gervais:
Well, I'm definately a 'Constant', and that's alot better than being a 'Variable' IHMO. http://forum.shrapnelgames.com/images/icons/icon12.gif

hmmm,.. but then again my post count is always changing, so I might be a 'variable' disguised as a 'constant'.

Come to think of it, many of the people here would best be described as 'Regulars',..

<font size="2" face="Verdana, Helvetica, sans-serif">Yeah, a variable can be static, or it can be const, and also a variable can be a member.

Stone Mill June 9th, 2003 05:04 AM

Re: # of members ?
 
In this forum, you can be bailed out at any given time when you stumble into a scientific discussion. Gotta love it! http://forum.shrapnelgames.com/images/icons/icon7.gif

Fyron June 9th, 2003 06:12 AM

Re: # of members ?
 
Quote:

Originally posted by PvK:
I think you need to study anti-logic to quantify Fryon. http://forum.shrapnelgames.com/images/icons/icon12.gif

PvK

<font size="2" face="Verdana, Helvetica, sans-serif">Not sure who this Fryon is... but it is quite impossible to quantify a person. http://forum.shrapnelgames.com/images/icons/tongue.gif

Kamog June 9th, 2003 07:22 AM

Re: # of members ?
 
Is the gravitational constant really constant?

Jack Simth June 9th, 2003 07:39 AM

Re: # of members ?
 
Quote:

Originally posted by Kamog:
Is the gravitational constant really constant?
<font size="2" face="Verdana, Helvetica, sans-serif">To the best of my knoweledge, within a given system of units (e.g. metric: meters, seconds, kilograms; "English": feet, seconds, slugs) the gravitational constant is constant. However, we have only had the tools to measure it for a fairly short period of time, and only on Earth.


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