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Re: # of members ?
And around earth, and all over the solar system, and all over the galaxy...
If the gravitational constant was different over at alpha centauri, for example, then the stars would be orbiting each other at the "wrong" speed. PS: And, variables can also be functions in certain cases. [ June 09, 2003, 14:15: Message edited by: Suicide Junkie ] |
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Wait I thought that there was only Fyron. At that the rest of us are just sub personalities or figments of his imagination.
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No silly, we are all Puke. http://forum.shrapnelgames.com/images/icons/icon6.gif
And the gravitational constant is indeed constant everywhere. We may not have the exact value down to the nanometer (and probably never will), but that doesn't really matter. http://forum.shrapnelgames.com/images/icons/icon12.gif |
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[ June 09, 2003, 18:57: Message edited by: Jack Simth ] |
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Star masses can also be found by looking at colour, age, size, etc.
And having a third body in the system to observe helps a lot. G can be calculated from the masses, distance between, and the observed acceleration. [ June 09, 2003, 21:14: Message edited by: Suicide Junkie ] |
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Without knowing both the masses and G, some simple numerical manipulation on the gravitational formulas can tell you that the distance and acceleration alone won't help: F = G(M*m)/(d^2) F' = G'(M'*m')/(d'^2) A = F/m = (G*M)/(d^2) A' = F'/m' = (G'*M')/(d'^2) If A = A' and d = d', then (G'*M')/(d^2) = (G*M)/(d^2) -> (G'*M') = (G*M) Example: Suppose G' = 2G: -> 2G*M' = G*M -> 2M' = M -> M' = M/2 Then M' = M/2 results in the same acceleration for the same distance. The number of bodies won't make a difference for this aspect of things. |
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Man did this one get DEEP! (way over my head)
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Well, I consider my reading the Forum as active. I try to read it every day. However, I only post occassionally, usually because someone has already made the point I was going to make and I don't want to just say, "yea, me too!"
Greybeard http://forum.shrapnelgames.com/images/icons/icon10.gif http://forum.shrapnelgames.com/images/icons/icon10.gif http://forum.shrapnelgames.com/images/icons/icon10.gif |
Re: # of members ?
Gravity is not the only force out there, so if gravity is off, and mass is off to compensate, you'll also have to adjust just the speed of light (E=MC^2), the electromagnetic, weak and strong nuclear forces, etc because the mass of nucleons has all changed.
Is that really what you meant to imply? I am not a physicist, but I suspect you'd be hard pressed to find a stable universe with different constants and still have anything close to the same observations made. [ June 10, 2003, 14:46: Message edited by: Suicide Junkie ] |
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