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Originally posted by Loser:
The gravity of a shell is not precieved by objects within the shell. For this reason, the gravity you experience will grow less and less as you penetrate deeper and deeper into a body such as the Earth.
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Gravity applies inside a shell, but if you're inside, the shell's gravitation comes from all sides, so some of it cancels out some of the rest. It then depends on where you are within the shell, and whether the shell is of uniform density or not. A Dyson sphere's own gravity would be a major factor in its engineering.
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...From the outside, the shell will will be an immense amount of gravity. But if the outside surface is spinning, and it will be spinning much faster than the earth's orbital velocity, then at the equator one would be thrown off at around 1 G.
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Naturally. If you design the spin so interior objects have a 1G acceleration towards the inside, then objects on the outside will fly off at 1G. On a ringworld, or the equator of a sphereworld with no scifi artificial gravity on the equator.
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In thruth it would be pretty damn hard to ladn on, you'd have to be on one wicked eliptic... though I could have the scale wrong.
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Certainly it'd a much simpler problem than assembling the contraption in the first place.
Try flying through a docking port and landing on the inside.
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Additionally, no human would be able to run or jump fast enough agaisnt the spin of the world to escape it and start floating. I believe, in order to get the 1 G, you'd have to be cranking damn fast.
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Try jumping off the Earth (no offense; I only suggest it because I'm sure you won't succeed) - it's exactly the same amount of difficulty - that's the point.
PvK