
December 24th, 2003, 09:20 PM
|
 |
Shrapnel Fanatic
|
|
Join Date: Jul 2001
Location: Southern CA, USA
Posts: 18,394
Thanks: 0
Thanked 12 Times in 10 Posts
|
|
Re: OT: Home Sick for the Holidays, or Probability and Yahtzee
Quote:
IIRC, the odds for multiple dice with separate outcomes for each are calculated by multiplying the individual odds; i.e., the odds for rolling a Yahtzee (all 5 d6 on same number) in a single roll would be 1/6^5, or 1/7776. However, it's been quite some time since I've studied probability, so I don't remember if that's correct.
|
That is correct.
Rolling 6 dice at once or 1 die at a time six times makes 0 difference.
There will never be a guarantee of getting that 1 or 6.
|