December 26th, 2003, 08:22 PM
|
 |
General
|
|
Join Date: Apr 2001
Location: Cincinnati, Ohio, USA
Posts: 4,547
Thanks: 1
Thanked 7 Times in 5 Posts
|
|
Re: OT: Home Sick for the Holidays, or Probability and Yahtzee
Quote:
Originally posted by Krsqk:
IIRC, the odds for multiple dice with separate outcomes for each are calculated by multiplying the individual odds; i.e., the odds for rolling a Yahtzee (all 5 d6 on same number) in a single roll would be 1/6^5, or 1/7776. However, it's been quite some time since I've studied probability, so I don't remember if that's correct.
|
Wouldn't it be 6/7776, or 1/1296, since there are six mutually exclusive ways to score a Yahtzee (five ones, five twos, five threes, etc.)?
If you want, you could always write a program to run through all the permutations and check whether they match any of the scoring combos... I've written two Yahtzee programs myself so I could always borrow something from one of those and just run all the permutations through a loop instead of generating them randomly... 
__________________
The Ed draws near! What dost thou deaux?
|