OK, let's see, centripetal acceleration is equal to, umm,
a = v^2 / r, and in circular motion velocity
v = 2 * pi * r / t, so substituting that expression for v,
a = 4 * pi^2 * r / t^2 (yep, the units check, distance over time squared), and substituting in your values,
a = 4 * pi^2 * 750m / (5s)^2 = 1,184 m/s^2... or about 120 times the earth's gravity. So if I'm not mistaken, he'd be squashed.
edit: now if the ship were several light seconds across...
[ November 10, 2003, 19:38: Message edited by: Ed Kolis ]