[liga]

In your analysises you have forgotten the permutations ... so for a SPECIFIC path you have

6+ 1/4 to the power of 6 ~ 0.02%
5+ 1/4 ^ 5 * 3/4 ~ 0.07 % times 6 ~ 0.4 %
4+ 1/4 ^ 4 * 3/4 ^ 2 ~ 0.2% times 15 ~ 3.3 %
3+ 1/4 ^ 3 * 3/4 ^ 3 ~ 0.7 % times 20 ~ 13.1 %

so it means that you have 13.1 + 3.3 + 0.4 ~ 17 %

to have a mage that is at least 3 in a single path ... if you are not insterested in a specific path it is 68 % ...

so more that 2 mage every 3 are at least 3+ in something with a 6 elemental random ... too strong!

good play
Liga

Post Edited: ooops ... I have seen only now the Last post

[ August 02, 2004, 15:16: Message edited by: liga ]