Quote:
Jack Simth said:
Kamog, I don't mean to be picky, but if you have decimal exponents available to do the e^ portion, you don't need logarithms at all:
sqrt (x) = x^(0.5)
- it's a basic identity.
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Hmm, that's a good point.
Yeah, I know that identity. Actually I started off with it to get the equation:
y = x^0.5
ln(y) = ln(x^0.5)
ln(y) = 0.5*ln(x)
y = e^(0.5*ln(x))
I see what you mean, why use logarithms if you have decimal exponents available.