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Old July 3rd, 2005, 08:56 PM
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Default Re: Multiple Defending Units?

#defmult1 15 givers 15/10 = 1.5 units per pd, so 1, 3, 4, 6,...

#defmult1 5 gives 5/10 = 0.5 units per pd, so 0,1,1,2,2,3,3,4,4,...

#defmult1 10 gives 1 unit per pd, so 1,2,3,4,5,...

If I understood Arralen's question right, this should answer it.
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