[narf poit chez BOOM]

Let's see if I can de-rust my brain...

Ok, we have: (1/2)(Ax - Ax)(T^2)+(Vx - Vx)T+(Sx- Sx) = 0

Which can be shortened down to (1/2) * A * T^2 + V * T + P = 0
A being Relative Acceleration,
T being Time,
V being Relative Velocity,
P being Position. Because using an S is not intuitive for me.

Why is it equal to 0, though? Pulling numbers out of a hat,
1/2 * 5 * 3^2 + 15 * 3 + 50
2.5 * 9 + 45 + 50
22.5 + 45 + 50
117.5

Um, not equal to zero. That would be total distance covered.
So: (1/2) * A * T^2 + V * T + P = D
D being Total Distance

(1/2) * A * T^2 - D + P = V * T?
1/2 * 5 * 3^2 - 117.5 + 50 = 45?
2.5 * 9 - 117.5 + 50
22.5 + -117.5 + 50
-45

Er, well, sorta. Except that should probably be positive. Also, the reply form should be larger.

(1/2) * A * T^2 + D - P = V * T?
1/2 * 5 * 3^2 + 117.5 - 50 = 45?
2.5 * 9 + 117.5 - 50
22.5 + 117.5 + -50
90

Nope...However, it would work for (1/2) * A * T^2 - D + P = -(V * T)

How am I doing so far?