Re: full coverage armor
okay, using better math this time.
where density = 1, mass = volume. v=4/3*pi*r^3, therefore r=(mass/((4/3)*pi))^(1/3)
and area=4*pi*r^2
so still using 1/500 mass, a 200KT hull takes a 1.31% size armor component, and a 15000KT hull takes a 0.311% size armor component.
much better, though 1/500 mass might be a bit small.
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