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				August 22nd, 2003, 12:54 AM
			
			
			
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 Lieutenant Colonel |  | 
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				 Re: Scam Or Not? 
 
	Yeah, like searching the registry for every occurance of "Messenger"Quote: 
	
		| Originally posted by dogscoff: I always strip MSN and MSMessenger off all my systems at the earliest opportunity. Microsoft tries very hard to stop you doing this (for example, on XP messenger has no uninstall function) but if you're determined there's always a way...
 |   I finally got those dratted Messenger popups to stop.
				__________________ 
				The Unpronounceable Krsqk
 
"Well, sir, at the moment my left processor doesn't know what my right is doing." - Freefall |  
	
		
	
	
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				August 22nd, 2003, 01:01 AM
			
			
			
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 Shrapnel Fanatic |  | 
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				 Re: Scam Or Not? 
 Umm... ever opened "msconfig" from the run prompt? Or perhaps the Services Manager from the Admin Tools? msconfig can control what programs start up with Windows. The Services Manager can control when Windows services (such as Messenger) start. No registry editing needed (at least, not manually     ). |  
	
		
	
	
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				August 22nd, 2003, 01:52 AM
			
			
			
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				 Re: Scam Or Not? 
 
	They could, it's just a matter of the computer time required.  The standard algorythm for removeing duplicates goes something like:Quote: 
	
		| Originally posted by DavidG: The biggest software company in the world that has written some of the most complex programs can't remove duplicate addresses from a list???  What's wrong with this picture.
 |  
 code:If they have 10^9 entries, the statement
 for(i=0; i<max; i++){
 for(j=i-1; j>=0; j--)
 {
 if(entry(i) == entry(j))
 {
 clear(i)
 }
 }
 }
 
 
 code:gets run, at most (1 + 2 + 3 + 4 + 5 + ... + ((10^9)-1) +(10^9)) times - roughly (10^9)^2, or about 10^18 times.  As it is almost impossible to hold 10^9 e-mail addresses in live memory at once (if you allow, say, 100 bytes per entry, that works out to 10^11 bytes - about one hundred gigabytes - of RAM for a single project; not likely), disk access times need to be used for dealing with the entries.  If you then assign a disk acess time of, say, 10^-6 seconds per entry, and multiply that by the number of entries accessed (roughly 10^18 accesses) you get an estimate on the amount of time the algorythm will take:  10^12 seconds.  That's roughly 16,666,666,666 minutes, 277,777,777 hours, 11,574,074 days, or 31,688 years.  Throw 10,000 machines at the task, and it still takes a little over three years (actually, more than that, due to communication time between them).  It isn't that they couldn't, it's just that it would cost more resources to eliminate the duplicates than doing so would save them.
 if(entry(i) == entry(j)) 
 
 Granted, there are several ways to shave time off of the above analysis, but that just gives a general idea of what it would take.
				__________________Of course, by the time I finish this post, it will already be obsolete.  C'est la vie.
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				August 22nd, 2003, 01:59 AM
			
			
			
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				 Re: Scam Or Not? 
 You do not have to load every single address into active memory at once. In fact, with that loop, each address is deleted from active memory (essentially) after it is checked against the one you are comparing it to.
 [ August 22, 2003, 01:00: Message edited by: Imperator Fyron ]
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				August 22nd, 2003, 02:18 AM
			
			
			
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				 Re: Scam Or Not? 
 
	Apparently you missed the numerous disclaimers:Quote: 
	
		| Originally posted by Imperator Fyron: You do not have to load every single address into active memory at once. In fact, with that loop, each address is deleted from active memory (essentially) after it is checked against the one you are comparing it to.
 |  rather than "is"; my note at the bottom
 
	and the  to indicate it was a worst-case (for that algorythm, worst-case = no duplicates) analysis.Quote: 
	
		| Granted, there are several ways to shave time off of the above analysis, but that just gives a general idea of what it would take. |  
 In the worst case, the Last entry checked must be checked against every other entry, and so all must be available (in memory, or accessed from the disk).  The point was to give a general idea of what was required, not the exact algorythm needed.  Things would be further complicated by the likelyhood that it isn't a matter of a single database of addresses being worked with.  There are a zillion (exaggeration) assumptions in my analysis, and several valid shortcuts that could be built into the algorythm.  It's an estimate to support what I said that DavidG had doubts about, not an exact analysis for that particular number set.
				__________________Of course, by the time I finish this post, it will already be obsolete.  C'est la vie.
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				August 22nd, 2003, 02:22 AM
			
			
			
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				 Re: Scam Or Not? 
 
	They could, it's just a matter of the computer time required.  The standard algorythm for removeing duplicates goes something like:Quote: 
	
		| Originally posted by Jack Simth: 
 quote:Originally posted by DavidG:
 The biggest software company in the world that has written some of the most complex programs can't remove duplicate addresses from a list???  What's wrong with this picture.
 |  
 Well I'm not going to dispute your math (frankly I didn't take the time to really understand it
  )  But I have MSN Messanger at work.  I signed up for the service and provided my e-mail adress to MS exactly ONE time.  And yet I got that message 10 times.  Face it MS got something screwed up.  Other corps with large databases seem to get things OK. (like Symantec) |  
	
		
	
	
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				August 22nd, 2003, 02:25 AM
			
			
			
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				 Re: Scam Or Not? 
 
	Perhaps this is the problem.  Now surely this shouldn't be hard to avoid.Quote: 
	
		| Originally posted by Jack Simth: However, apparently, it's possible to get on their lists more than once
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