pan cw : formulas for freespawns/reanimations. quite finished . with guide too

[Boron]

ok i had a faerun sp game left which i don't want to continue :
so i did some testing there :
my results are surprising :

i had dominion strenghts 8 , growth 1 , the testing province was a wood and unburied corpses there .

i had 11 lvl 3 unholy reanimators in that province too .


after ligas formulas as far as i understood them the following should be :

because of unburied corpses :
10x(8+1+1) % chance = 100% chance for a d10 roll
that means 1-10 freespawns
because of forest location the same , again 1-10 freespawns .

from reanimation :
2 variants :
lvl 3 priest/2 = 1,5

variant 1 :
rounded up to 2 :
2+(1d2-1) = 2-3 summons per reanimation
variant 2 :
rounded down to 1 :
1+(1d2-1)= 1-2 summons per reanimation


so i should get according to ligas formulas :
variant 1 : 24-53 new creatures in the province
variant 2 : 13-42 new creatures in the province


now what i did get was the following :
i did 6 turns and each turn i got exactly 35 new creatures .
it is in ligas formulas ranges but because the range is exactly 29 figures .
there are many possible outcomes , at least more than 1000 , probably much more .
now the important point though :
the exact outcome of 35 has something like a 5-10% probability at maximum .
even if it would be 10% probability my outcome of 35 for 6 following turns would have the following probability because the turns are independent :

6
(0,1) = 0.0001 %

so the formula seems incorrect .

i have found a very simple formula for myself now which fits very well with the outcome :


creatures per reanimation : simply unholy priest level
1x[10(dominionstrenghts+growth+1)] % chance for 1 freespawn because of forest

1x[10(dominionstrenghts+growth+1)] % chance for 1 freespawn because of unburied corpses .


so far the result is : 11x3 creatures through reanimation + 1 for forest + 1 because of unburied corpses = 35 .

[ July 30, 2004, 16:00: Message edited by: Boron ]