Newbie Slug Fest - Mose Hansen game - ENDED

[PashaDawg]

The Panther said:

If my daughter becomes a lawyer some day, I wonder if I will then be able to trust lawyers???

NAWWWWWWWWW!!!!!

Oh - - Panther - - - what kind of engineer are you? Chemical? Electical? Structural? Computer? Sanitation? Choo-Choo? (Ignore me if I am getting too nosey or silly.)

[The Panther]

BS Nuclear and MS electrical. I work at a nuclear weapons research facility, actually. But the nuclear weapons business has been extremely slow since the end of the Cold War. Currently, I have drifted into Program Management for non-proliferation research and engineering efforts, primarily in nuclear radiation detection and characterization.

So, if you kill me in a game, I just might nuke you in return!

[PashaDawg]

The Panther said:
BS Nuclear and MS electrical. I work at a nuclear weapons research facility, actually. But the nuclear weapons business has been extremely slow since the end of the Cold War. Currently, I have drifted into Program Management for non-proliferation research and engineering efforts, primarily in nuclear radiation detection and characterization.

So, if you kill me in a game, I just might nuke you in return!

Very cool! I think you definitely got me beat in the math and science department. I liked science in school, but now I just read National Geo.

[DragonFire11]

Really! I write boring motions for a living. And you mint nukes. Ok Mr. Smarty Panther: How do you calculate the area of a disk if it is spinning? (I don't know the answer so you could make just about anything up.)

[The Panther]

Measure the diameter of the disk. Divide by 2 and square the result. Multiply by PI (~3.14159). And that's all she wrote!

Makes no difference if it is spinning or not other than the difficulty in measuring it. It is actually more interesting if the disc has a hole in the middle like a CD.

So... A standard CD diameter is 12 cm on the outside, and just under 1.5 cm on the inside. The area of a spinning CD is therefore approximately:
(12/2) * (12/2) * PI = 113.1 sq cm
MINUS the hole
(1.5/2) * (1.5/2) * PI = 1.8 sq cm
Equals
111.3 sq cm
Which is the answer to the CD question.


And no, I am not making this up!

[DragonFire11]

Ah, well it should matter mathematically. If the disk is spinning, the outer edge is moving faster than the inner portion. As a result, the outer edge is heavier and more compressed, and distorting space more. Consequently, the irrational number of pi no longer exists – well it’s no longer useful other than an estimate. I have no standing to engage in a math discussion with you (beyond simple addition) but I think I am right about this.

[DragonFire11]

I know the Dawg will give me grief about this so I just want to say that the spinning means its not just a classic math problem but a question of relativity - spinning means the disk is no longer flat.

[The Panther]

DragonFire11 said:
Ah, well it should matter mathematically. If the disk is spinning, the outer edge is moving faster than the inner portion. As a result, the outer edge is heavier and more compressed, and distorting space more. Consequently, the irrational number of pi no longer exists – well it’s no longer useful other than an estimate. I have no standing to engage in a math discussion with you (beyond simple addition) but I think I am right about this.

Ah, the classic difference between a scientist and the engineer. The scientist sits around trying to figure exact answers to questions which are meaningless. The engineer simply estimates the correct answer and then goes on to build the disc.

Actually, the effects of the manufacturing tolerances dwarfs (by many orders of magnitude) the nearly infitintesimal area modification caused by the outer stretching in a spinning CD. In fact, the Heisenberg Uncertainity Principle will tell you that the difference is likely not even measurable! Which means is matters not to the engineer, but only the scientist!