Stealth Mathematics

[Illuminated One]

Thanks.

So this is the average number of eyes when throwing two open-ended dice?

Since I'm looking for the probability to beat the opposed roll against a fixed difference between stealth and destealth, I don't know if that helps though.

Hmm, I've tried to do it without oe and I came up with the following formula. The chance to roll x (as long as x < 52 afterwards) with 4 25 sided dice is (well, if I didn't make a mistake)

P(x) = ((x - 4) * (x - 2) * 3 * x - (x - 3) * (x - 2) * (2*x - 5) )/6*25^4

With that and excel one could make a table for non oe dice.