Re: Height Maps
I am posting this here since i am working on a map generated from the Venhola map tool.
From the WINSPMBT Game Guide:
Terrain, hills and LOS
Each level of hill in the game is broken down into 10 units. Ground level terrain that is "5" high is midway to being a level 1 hill. Level 1 terrain that reports as being "15" high is midway to being a level 2 hill etc, etc to the top level ( level 15 )
The game does not block LOS behind a "bump" in the map until it gets to be 4 higher than the base height for that level ( ground level would be 4, level 1 would be 14, level 2 would be 24 etc etc. ). It will allow you to see over and behind any "bump" 3 and under so any terrain 3 and under above the level you are on will offer neither cover nor concealment.
For example.....
If a unit is at zero height directly behind a 4 high "bump" that is three hexes long , LOS will be blocked for 2 hexes behind the bump. If that 4 high bump is 4 hexes long, LOS will be blocked completely right across the map. If the bump is 5 high even one hex will totally block LOS.
We are currently considering that each unit of height roughly represents 24 inches or .6 meters. As a simple rule of thumb this would make each hill level represent roughly 20 feet or 6 meters of height
So:
Height 1 = 20 feet/6 meters
2 = 40/12
3 = 60/24
4 = 80/30
5 = 100/36
6 = 120/42
7 = 140/48
8 = 160/54
9 = 180/60
10 = 200/66
11 = 220/72
12 = 240/78
13 = 260/84
14 = 280/90
15 = 300/96
The reason for my seemingly grognard questioning is I am working on a map that highest peaks need to be 656'/200m and I need to set the ratio to translate the scale to WINSPMBT height system. I am calculating that if level 15 300'/96m will be simulating the 656'/200m then each 100'/33m of real height should be a 2.5 level increase on the map. Sounds good?
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