OT: would anyone happen to know how to calculate bouncing a ball off an angled box?

narf poit chez BOOM · #1 September 12th, 2003, 08:07 PM

would anyone happen to know how to calculate bouncing a ball off an angled box?

[ September 12, 2003, 19:08: Message edited by: narf poit chez BOOM ]

Erax · #2 September 12th, 2003, 08:21 PM

Possibly, but I need more details.

narf poit chez BOOM · #3 September 12th, 2003, 08:38 PM

ok, right now what i've got is a 3d setup, but i'm only using the x and z planes. i generate a ball at the bottom-left corner of the screen and send it at an angle from 0-90 into a bunch of boxes. the boxes are currenty square and not angled, but what i want is to randomly shoot in balls from all sides of the screen and have them bounce off rectangular boxes.

Erax · #4 September 12th, 2003, 08:49 PM

Easy, the incoming and outgoing angles are always equal. I can make a drawing when I get home, but for now imagine an underlined V. The underline is the box surface and the V is the ball's trajectory. Now the angle from the left side of the underline to the left of the V must be equal to the angle from the right side of the underline to the right side of the V.

This in 2-D, which is what you are using, right ?

Alneyan · #5 September 12th, 2003, 08:58 PM

*Looks at the thread* *Runs away in terror* Please, Narf, you could add a warning in the title for the ones like me who have issues with this kind of... things.

narf poit chez BOOM · #6 September 12th, 2003, 09:10 PM

well, the objects are 3d, but it's on a flat plane.

ok, so i figure out what angle the wall is at, then:

wall at 45 degrees, ball comming in at 90, 45-90=-45, 45+-45=0. ball coming in at 270, 45-270=-225, so, if negative 360+-225=135? doesn't work there. but, since it's hitting the bottom...angle at 225, same tilt, 225-270=-45, 225--45=270. doesn't work.

i missed something, right?

what more warning do you want?