I understand that but I don't see how that applies to the argument. Your saying 255 systems takes up X amount of space if you use 8 bit numbers, then you say 16 bit numbers takes up much more than 2X the space.
Your argument hold true
if your talking about the number of
POSSIBLE combinations, not what the
actual memory requirement is. The memory requirement is linear with byte size if you keep the same number of variables for the system, the
possible combinations is exponential with byte size since you have twice the number of bits, you have as you said, a lot more combinations.
But we're not talking about combinations, we're talking about straight storage, right? Or did I miss the point entirely?
quote:
Originally posted by LemmyM:
if you have 8 bits then you have 2 to the 8th possible numbers, that is 256
if you have 16 bits, you have 2 to the 16th possible numbers, that is 65535
so it's not just twice as much, the difference in bits is 16 - 8 = 8, so it is 2 to the 8th times as much
and 70 mb is of course the maximum, if you actually have 65536 systems in a map
[This message has been edited by LemmyM (edited 08 May 2001).]
Re: Could someone explain:
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