Strategy guide?

[Spyder]

Yeah, but, that squirrel needs an ignition device and some sort of chain-reaction accelerator (usually provided by Tritium)....he then becomes a Voting member of the UN

Spyder, Chairman of the Arachnid Consortium

[This message has been edited by Spyder (edited 26 February 2001).]

[Suicide Junkie]

Arggh! Don't you see?

The 50 Million Tons of TNT you pile up and explode turns into:

(50 Million Tons - 1 KG) of ash.

A 500KG Nuke rated at 50Megatons would turn into

(500KG - 1KG)= 499KG of ash.

The 1KG squirrel that releases a 50Megaton BLast turns into

(1KG - 1KG) = 0Kg of ash


A 50Megaton bLast is 9x10^16 J of energy
THEREFORE, a 50Megaton bLast is 1KG of Mass going byebye as energy.

This is not a nuclear squirrel, but an antimatter squirrel. That's the only way to get a 50Megatons bLast out of 1Kg of material.

E=MC^2 means that for your 50MT bLast, your mass goes down by 1KG. if you started with 1KG, you have ZERO mass left. The only way for that to happen is matter-antimatter annihilation.

Now, by measuring the energy released, you also happen to be measuring the mass lost by the device. (Since M=E/C^2)

Even for nukes, the mass lost is a tiny fraction of what you started with. All that means is that nukes are horribly inefficient at generating energy.

[tictoc]

Wow.

tic

[Spyder]

Well, I TRIED to lighten this, but.....<shakes his head>

Suicide Junkie....Unless I dramatically failed Physics and didn't know it...E=MC^2 is the formula with which you convert matter to energy. It has nothing to do with loss of mass during a nuclear reaction (there's a whole nother, page-long, equation for that ).

Spyder, Chairman of the Arachnid Consortium (A Nuke-free Society)

[Triumvir Emphy]

Please sir,... mercy mercy,... my he'd 'urts
no more science explanations pleazzzzzzzzz

(nice squirell by the way)

[Lastseer]

From what I understand the loss of mass in a nuclear reaction is converted directly to energy at E=mc^2. That is party what makes a nuclear explosion so powerful. When the nucleous is split (where talking fission) here the resulting smaller nucleii don't add up to the same mass. The rest is pure energy. Of course this is usually a small fraction of the original critical mass. (btw this is usually on the order of fractions of grams if I remember correctly).

That is why anti-matter bombs are potentially so powerful (atleast 100's to 1000's times more powerful than nuclear fission devices). Because instead of losing a small amount of matter in the explosion you get 100% conVersion or the orignal mass (not less than 1%).

[Spyder]

quote:

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Originally posted by Lastseer:
From what I understand the loss of mass in a nuclear reaction is converted directly to energy at E=mc^2. That is party what makes a nuclear explosion so powerful. When the nucleous is split (where talking fission) here the resulting smaller nucleii don't add up to the same mass. The rest is pure energy. Of course this is usually a small fraction of the original critical mass. (btw this is usually on the order of fractions of grams if I remember correctly).

That is why anti-matter bombs are potentially so powerful (atleast 100's to 1000's times more powerful than nuclear fission devices). Because instead of losing a small amount of matter in the explosion you get 100% conVersion or the orignal mass (not less than 1%).

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Yep, I'll buy that...its figuring exactly how much mass is lost (as energy) that is the long formula of which I spoke. Of course, I'm old & gray and don't remember much....

Spyder, Chairman of the Arachnid Consortium