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  #1  
Old May 19th, 2003, 03:44 PM
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Default Re: POLL Who has the funniest Sig

Having read Geo's post first, I was trying to understand what cruel individual would put "Click here to donate to Play By Web" on the funniest sig list.
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Old May 19th, 2003, 03:57 PM

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Default Re: POLL Who has the funniest Sig

Nodachi sig made me laugh the longest, but all of them are top notch.
Tesco's sig should get an especial award for linking sig and avatar.
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Old May 19th, 2003, 04:18 PM
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Default Re: POLL Who has the funniest Sig

Yay, I got my smpathy vote. The rest of you are free to vote your conscience now.
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Old May 19th, 2003, 05:51 PM
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Default Re: POLL Who has the funniest Sig

Ahhhh...I've fallen into a third place tie...Oh well, I knew I wouldn't beat the others out.
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Old May 19th, 2003, 05:53 PM

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Default Re: POLL Who has the funniest Sig

geo - dun worry, your sig is amongst the best outa there, just its aint the funniest
AND, my vote remains for Rags (not that i can change it )

Fyron yes i know, but hey, its still lotsa energy!
EDIT: dont you need to make it go at 3x10^8m/s?

[ May 19, 2003, 16:55: Message edited by: Taera ]
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  #6  
Old May 19th, 2003, 06:39 PM
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Default Re: POLL Who has the funniest Sig

Quote:
Originally posted by Taera:
geo - dun worry, your sig is amongst the best outa there, just its aint the funniest
Also, note that best and funniest are far from being the same thing.
Quote:
Originally posted by Taera:

AND, my vote remains for Rags (not that i can change it )

Fyron yes i know, but hey, its still lotsa energy!
EDIT: dont you need to make it go at 3x10^8m/s?
Not quite, partially because c is slightly less than 3x10^8 m/s (not that it matters too much), partially because at c an object, regardless of rest mass (as long as it is non-zero) would have infinite energy (side note: it would require infinite energy to get it up to that velocity, so you haven't really gained anything that way); the formula is something like:

(1/(sqrt(1 - (v^2)/(c^2))))m(c^2)

As v approches c, (v^2)/(c^2) approaches 1, 1 - (v^2)/(c^2) approches 0, so 1/(sqrt(1 - (v^2)/(c^2))) approaches infinity. Multiply infinity by a positive nonzero number, such as m(c^2), and you get infinity.

Nah, to totally convert the squirrl, you would either need to bump it up against an anti-matter squirrl or to it or toss it into a black hole and get the energy out slowly via Hawking Radiation. There might be another method that is presently unknown, but don't hold your breath waiting for it to be discovered; such discoveries usually take a long, long time.
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Old May 20th, 2003, 03:37 AM
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Default Re: POLL Who has the funniest Sig

Quote:
Originally posted by geoschmo:
Yay, I got my smpathy vote. The rest of you are free to vote your conscience now.
Got mine, too, Geo... .

But, as I said, though not the Oscars ( ), it's nice to be nominated!
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