Narf's Mod: Almost done shredding the Facility.txt. Basic stuff only.

[Jack Simth]

Originally posted by Imperator Fyron:
Yes, but objects falling within the atmosphere don't behave the same as two large objects in space attracting each other... The reason why objects fall at the same rate is that he gravitational acceleration caused by the earth's gravity is constant (at the same point on the surface of the earth, relative to two different objects). This is in part because the falling objects have infintesimal mass compared to that of the earth (though technically they do actually move the earth an infintesimal distance closer to themselves as they fall ). Objects in space are governed by the relation F = G * M1 * M2 / r^2, where F is force, G is a constant, M1 and M2 are the masses of the two objects, and r is the distance between them. A more massive object causes more gravitational force between the objects, and thus greater acceleration.

They only accelerate faster relative to each other, because both are accelerating at a rate dependant only on the other's mass. When both are massive; from a "fixed" perspective, the acceleration a body recieves depends only on the mass and distance of the bodies affeting it (until you get into relativity; but that takes extreme circumstances e.g. black holes vs. rotating black holes). You can get this fairly simply by recalling that Acceleration = F/M. For mass 1, A1 = F/M1 = (G * M1 * M2 / r^2)/M1 = (G * M2 / r^2); for mass 2, A2 = F/M2 = (G * M1 * M2 / r^2)/M2 = (G * M1 / r^2). If you are on M1 and using M2 as your referance, your acceleration = A1 + A2 = (G * M1 / r^2) + (G * M2 / r^2) = G(M1 + M2)/r^2.

[narf poit chez BOOM]

so i won't be able to scale the supply on a bonus movement engine? thought it would be a problem. then thought, if they ignore ship size, then naturally there supply usage will only be reletive to there movement bonus not ship size.

well, the main point for the engine is to have an engine that provide's the same movement to all ships, regardless of size.

shouldn't there be brackets? from what i remember from science, there should
F = (G * M1 * M2) / r^2

so, since my gravitic engine idea currently works by generating a gravity field, that would be
F = (G * M1 + GF) / r^2, where GF is gravity field.

so, the additional pull provided by a larger ship would be balanced out by the additional inertia. so same movement for all ships. works.

what i'm not looking forward to is reworking all the supply usages so a baseship uses more supply than an escort.
ok, Jack's managed to confuse me. hey Jack, can you take a look lower in the thread and tell me if you understand my math there? because i'm not sure if i do.

[ October 27, 2003, 23:04: Message edited by: narf poit chez BOOM ]

[Phoenix-D]

Bonus movement IIRC doesn't ever use suppplies.

[narf poit chez BOOM]

hmm...make them really big and costly?

called them 'displaced gravitic drives'.

[Fyron]

Umm... the parenthesis are irrelevant when it is all multiplication and division (and the division is done after the multiplication from left to right). F = (G * M1 * M2) / r^2 is the same as F = G * M1 * M2 / r^2

Though if you want to get technical, it is usually written as:

code:

---

       M1 * M2

F = G ---------

         r^2

---

[ October 27, 2003, 23:24: Message edited by: Imperator Fyron ]

[Jack Simth]

Originally posted by narf poit chez BOOM:
shouldn't there be brackets? from what i remember from science, there should
F = (G * M1 * M2) / r^2

so, since my gravitic engine idea currently works by generating a gravity field, that would be
F = (G * M1 + GF) / r^2, where GF is gravity field.

No; if the GF simulates a mass at some distance, then it should be F = (G * M1 * GF) / r^2, or A = (G * GF)/r^2 - although it is a rather moot point, as SE doesn't allow you to model acceleration, only set velocities. There is a catch to the equation, however - bigger ships are bigger, and r is the distance between the effective center of gravity between the two objects; the GF must be generated beyond the hull to have full impact; otherwise, the portion of the force on the portion of the hull beyond the GF is countering some of the force on the portion of the hull not beyond the GF. Thus, larger ships require a larger r to be effective, but that reduces the force on the ship (bigger r -> slower ship for same drives). If r is constant for all ship sizes, then the exact same gravity drive that moves your worldship will move your frigate at the same speed. Otherwise, the frigate would be faster.

Originally posted by narf poit chez BOOM:

so, the additional pull provided by a larger ship would be balanced out by the additional inertia. so same movement for all ships. works.

Essentially.

Originally posted by narf poit chez BOOM:

what i'm not looking forward to is reworking all the supply usages so a baseship uses more supply than an escort.
ok, Jack's managed to confuse me.

Sorry about that; mathmatical symbol manipulation confuses a lot of people. I'm not really sure how to make myself clearer; I used essentially the same symbols Fyron did, if that helps any.

Originally posted by narf poit chez BOOM:
hey Jack, can you take a look lower in the thread and tell me if you understand my math there? because i'm not sure if i do.

Is this one the one you mean?

Originally posted by narf poit chez BOOM:
i just finished putting in 20 'normal' engines, based off of Ion Engine I with 10% increase. the size, costs and supply usage are modified by engine speed with (INT(E)/E)*#. supply usage decimals are ignored. maybe i should compensate for having a second ability which is close enough to 100% of actual number to be considered 100% by (((INT(E)/#)+100)/2)*#?

... if so, I haven't tried my hand at modding these, and am unfamiliar with what you mean by each symbol (E, INT(E), and #); a word translation table would be useful there.

[Renegade 13]

Is everyone here a math/physics expert? All those computations and equations....makes my head hurt

Renegade 13