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Old February 19th, 2005, 06:11 PM
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Default Re: Random Magic Paths - is it truly random?

Based on his knowledge of statistics he made an estimate, thats what the ~ is for.

The exact value is given by
((7/8)^20 * 8c7) + ((6/8)^20 * 8c6) + ((5/8^20 * 8c5) + . . . + ((1/8^20 * 8c1) = .647163

If he didn't figure it out exactly he's a pretty good guesser.

And he did say it properly:

Probability of not getting 1 or more paths after recruiting 20 random paths.

*8c5 = 8 combinataion 5 (ways to get 5 out of 8 with replacement) = 8!/5!3!
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